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Plot delta_lambda for a grid.¶
This script demonstrates how to generate delta_lambda from a provided grid. It includes the following steps: - Builds a parametric galaxy using make_sfzh. - Retrieves delta_lambda for the galaxy using the grid.
Mean delta: 0.0016621533964399108
import matplotlib.pyplot as plt
import numpy as np
from unyt import Msun, Myr
from synthesizer.emission_models import IncidentEmission
from synthesizer.grid import Grid
from synthesizer.parametric import SFH, Stars, ZDist
from synthesizer.parametric.galaxy import Galaxy
if __name__ == "__main__":
# Define the grid
grid_name = "test_grid"
grid_dir = "../../tests/test_grid/"
grid = Grid(grid_name, grid_dir=grid_dir)
# Define the emission model
model = IncidentEmission(grid)
# define the parameters of the star formation and metal enrichment
# histories
sfh_p = {"max_age": 10 * Myr}
Z_p = {
"log10metallicity": -2.0
} # can also use linear metallicity e.g. {'Z': 0.01}
stellar_mass = 1e8 * Msun
# define the functional form of the star formation and metal enrichment
# histories
sfh = SFH.Constant(**sfh_p) # constant star formation
metal_dist = ZDist.DeltaConstant(**Z_p) # constant metallicity
# get the 2D star formation and metal enrichment history for the given SPS
# grid. This is (age, Z).
stars = Stars(
grid.log10age,
grid.metallicity,
sf_hist=sfh,
metal_dist=metal_dist,
initial_mass=stellar_mass,
)
# Define redshift
z = 10.0
# create a galaxy object
galaxy = Galaxy(stars, redshift=z)
# Delta lambda model for pure stellar spectra
galaxy.stars.get_spectra(model)
lam, delta_lam = Grid.get_delta_lambda(grid)
print("Mean delta: ", np.mean(delta_lam))
figsize = (10, 5)
fig = plt.figure(figsize=figsize)
left = 0.15
height = 0.6
bottom = 0.1
width = 0.8
ax = fig.add_axes((left, bottom, width, height))
ypeak = np.min(delta_lam)
ylimits = np.mean(delta_lam)
ax.plot(np.log10(lam)[:-1], delta_lam, lw=1, alpha=0.8, label=grid_name)
xlim = [2.6, 4.2]
ylim = [ypeak - ylimits, ypeak + ylimits]
ax.set_xlim(xlim)
ax.set_ylim(ylim)
ax.legend(fontsize=8, labelspacing=0.0)
ax.set_xlabel(r"$\rm log_{10}(\lambda/\AA)$")
ax.set_ylabel(r"$\rm Δ(\lambda/\AA)$")
plt.show()
Total running time of the script: (0 minutes 0.383 seconds)